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x^2+48x-4200=0
a = 1; b = 48; c = -4200;
Δ = b2-4ac
Δ = 482-4·1·(-4200)
Δ = 19104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19104}=\sqrt{16*1194}=\sqrt{16}*\sqrt{1194}=4\sqrt{1194}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-4\sqrt{1194}}{2*1}=\frac{-48-4\sqrt{1194}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+4\sqrt{1194}}{2*1}=\frac{-48+4\sqrt{1194}}{2} $
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